std::move_backward
Defined in header <algorithm> | ||
|---|---|---|
template< class BidirIt1, class BidirIt2 > BidirIt2 move_backward( BidirIt1 first, BidirIt1 last, BidirIt2 d_last ); |
(since C++11) (constexpr since C++20) |
Moves the elements from the source range [first, last) to the destination range ending at d_last, starting from last and proceeding to first (reverse order).
If d_last is in (first, last], the behavior is undefined.
Parameters
| first, last | - | the pair of iterators defining the source range |
| d_last | - | the past-the-end iterator of the destination range |
| Type requirements | ||
-BidirIt1, BidirIt2 must meet the requirements of LegacyBidirectionalIterator. |
||
Return value
An iterator to the last move-assigned element in the destination range, or d_last if no element is moved.
Complexity
Exactly std::distance(first, last) assignments.
Notes
When moving overlapping ranges, std::move is appropriate when moving to the left (beginning of the destination range is outside the source range) while std::move_backward is appropriate when moving to the right (end of the destination range is outside the source range).
Possible implementation
template<class BidirIt1, class BidirIt2>
BidirIt2 move_backward(BidirIt1 first, BidirIt1 last, BidirIt2 d_last)
{
while (first != last)
*(--d_last) = std::move(*(--last));
return d_last;
}
|
Example
#include <algorithm>
#include <iostream>
#include <iterator>
#include <string>
#include <string_view>
#include <vector>
using container = std::vector<std::string>;
void print(std::string_view comment, const container& src, const container& dst = {})
{
auto prn = [](std::string_view name, const container& cont)
{
std::cout << name;
for (const auto &s : cont)
std::cout << (s.empty() ? "∙" : s.data()) << ' ';
std::cout << '\n';
};
std::cout << comment << '\n';
prn("src: ", src);
if (dst.empty())
return;
prn("dst: ", dst);
}
int main()
{
container src{"foo", "bar", "baz"};
container dst{"qux", "quux", "quuz", "corge"};
print("Non-overlapping case; before move_backward:", src, dst);
std::move_backward(src.begin(), src.end(), dst.end());
print("After:", src, dst);
src = {"snap", "crackle", "pop", "lock", "drop"};
print("Overlapping case; before move_backward:", src);
std::move_backward(src.begin(), std::next(src.begin(), 3), src.end());
print("After:", src);
}
Output:
Non-overlapping case; before move_backward: src: foo bar baz dst: qux quux quuz corge After: src: ∙ ∙ ∙ dst: qux foo bar baz Overlapping case; before move_backward: src: snap crackle pop lock drop After: src: ∙ ∙ snap crackle pop
See also
|
(C++20) | moves a range of elements to a new location in backwards order (algorithm function object) |
|
(C++11) | moves a range of elements to a new location (function template & algorithm function object) |
|
(C++20) |
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