std::chrono::duration<Rep,Period>::operator+=, -=, *=, /=, %=
duration& operator+=( const duration& d ); | (1) |
(since C++11) (constexpr since C++17) |
duration& operator-=( const duration& d ); | (2) |
(since C++11) (constexpr since C++17) |
duration& operator*=( const rep& rhs ); | (3) |
(since C++11) (constexpr since C++17) |
duration& operator/=( const rep& rhs ); | (4) |
(since C++11) (constexpr since C++17) |
duration& operator%=( const rep& rhs ); | (5) |
(since C++11) (constexpr since C++17) |
duration& operator%=( const duration& rhs ); | (6) |
(since C++11) (constexpr since C++17) |
Performs compound assignments between two durations with the same period or between a duration and a tick count value.
If rep_ is the member variable holding the number of ticks in this duration object,
1) Equivalent to
rep_ += d.count(); return *this;.
2) Equivalent to
rep_ -= d.count(); return *this;.
3) Equivalent to
rep_ *= rhs; return *this;.
4) Equivalent to
rep_ /= rhs; return *this;.
5) Equivalent to
rep_ %= rhs; return *this;.
6) Equivalent to
rep_ %= d.count(); return *this;.Parameters
| d | - | duration on the right-hand side of the operator |
| rhs | - | number of ticks on the right-hand side of the operator |
Return value
A reference to this duration after modification.
Example
#include <chrono>
#include <iostream>
int main()
{
std::chrono::minutes m(11);
m *= 2;
m += std::chrono::hours(10); // hours implicitly convert to minutes
std::cout << m.count() << " minutes equals "
<< std::chrono::duration_cast<std::chrono::hours>(m).count()
<< " hours and ";
m %= std::chrono::hours(1);
std::cout << m.count() << " minutes\n";
}
Output:
622 minutes equals 10 hours and 22 minutes
See also
| increments or decrements the tick count (public member function) |
|
|
(C++11) | implements arithmetic operations with durations as arguments (function template) |
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