std::chrono::operator+, std::chrono::operator- (std::chrono::year_month_day_last)
Defined in header <chrono> | ||
|---|---|---|
constexpr std::chrono::year_month_day_last
operator+( const std::chrono::year_month_day_last& ymdl,
const std::chrono::months& dm ) noexcept;
| (since C++20) | |
constexpr std::chrono::year_month_day_last
operator+( const std::chrono::months& dm,
const std::chrono::year_month_day_last& ymdl ) noexcept;
| (since C++20) | |
constexpr std::chrono::year_month_day_last
operator+( const std::chrono::year_month_day_last& ymdl,
const std::chrono::years& dy ) noexcept;
| (since C++20) | |
constexpr std::chrono::year_month_day_last
operator+( const std::chrono::years& dy,
const std::chrono::year_month_day_last& ymdl ) noexcept;
| (since C++20) | |
constexpr std::chrono::year_month_day_last
operator-( const std::chrono::year_month_day_last& ymdl,
const std::chrono::months& dm ) noexcept;
| (since C++20) | |
constexpr std::chrono::year_month_day_last
operator-( const std::chrono::year_month_day_last& ymdl,
const std::chrono::years& dy ) noexcept;
| (since C++20) |
1,2) Adds
dm.count() months to the date represented by ymdl. The result has the same year() and month() as std::chrono::year_month(ymdl.year(), ymdl.month()) + dm.
3,4) Adds
dy.count() years to the date represented by ymdl. The result is equivalent to std::chrono::year_month_day_last(ymdl.year() + dy, ymdl.month_day_last()).
5) Subtracts
dm.count() months from the date represented by ymdl. Equivalent to ymdl + -dm.
6) Subtracts
dy.count() years from the date represented by ymdl. Equivalent to ymdl + -dy.For durations that are convertible to both std::chrono::years and std::chrono::months, the years overloads (3,4,6) are preferred if the call would otherwise be ambiguous.
Example
#include <cassert>
#include <chrono>
#include <iostream>
int main()
{
auto ymdl{11/std::chrono::last/2020};
std::cout << ymdl << '\n';
ymdl = std::chrono::years(10) + ymdl;
std::cout << ymdl << '\n';
assert(ymdl == std::chrono::day(30)/
std::chrono::November/
std::chrono::year(2030));
ymdl = ymdl - std::chrono::months(6);
std::cout << ymdl << '\n';
assert(ymdl == std::chrono::day(31)/
std::chrono::May/
std::chrono::year(2030));
}
Output:
2020/Nov/last 2030/Nov/last 2030/May/last
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