operator+(std::move_iterator)

Defined in header <iterator>

Defined in header `<iterator>`
template< class Iter > move_iterator<Iter> operator+ ( typename move_iterator<Iter>::difference_type n, const move_iterator<Iter>& it );		(since C++11) (constexpr since C++17) (until C++20)
template< class Iter > constexpr move_iterator<Iter> operator+ ( std::iter_difference_t<Iter> n, const move_iterator<Iter>& it );		(since C++20)

template< class Iter >
move_iterator<Iter> operator+
    ( typename move_iterator<Iter>::difference_type n,
      const move_iterator<Iter>& it );

(since C++11)
(constexpr since C++17)
(until C++20)

template< class Iter >
constexpr move_iterator<Iter> operator+
    ( std::iter_difference_t<Iter> n, const move_iterator<Iter>& it );

(since C++20)

Returns the iterator it incremented by n.

This overload participates in overload resolution only if it.base() + n is well-formed and has type Iter.

(since C++20)

n	-	the number of positions to increment the iterator
it	-	the iterator adaptor to increment

it + n

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

DR	Applied to	Behavior as published	Correct behavior
LWG 3293	C++20	the non-member operator+ was constrained to require `it + n` is well-formed and has type `Iter`	changed to `it.base() + n`

operator++operator++(int)operator+=operator+operator--operator--(int)operator-=operator-	advances or decrements the `move_iterator` (public member function)
operator- (C++11)	computes the distance between two iterator adaptors (function template)