Control.Monad.Fix
| Copyright | (c) Andy Gill 2001 (c) Oregon Graduate Institute of Science and Technology 2002 |
|---|---|
| License | BSD-style (see the file libraries/base/LICENSE) |
| Maintainer | libraries@haskell.org |
| Stability | stable |
| Portability | portable |
| Safe Haskell | Safe |
| Language | Haskell2010 |
Description
Monadic fixpoints, used for desugaring of {-# LANGUAGE RecursiveDo #-}.
Consider the generalized version of so-called repmin (replace with minimum) problem: accumulate elements of a container into a Monoid and modify each element using the final accumulator.
repmin :: (Functor t, Foldable t, Monoid b) => (a -> b) -> (a -> b -> c) -> t a -> t c repmin f g as = fmap (`g` foldMap f as) as
The naive implementation as above makes two traversals. Can we do better and achieve the goal in a single pass? It's seemingly impossible, because we would have to know the future, but lazy evaluation comes to the rescue:
import Data.Traversable (mapAccumR) repmin :: (Traversable t, Monoid b) => (a -> b) -> (a -> b -> c) -> t a -> t c repmin f g as = let (b, cs) = mapAccumR (\acc a -> (f a <> acc, g a b)) mempty as in cs
How can we check that repmin indeed traverses only once? Let's run it on an infinite input:
>>> import Data.Monoid (All(..))
>>> take 3 $ repmin All (const id) ([True, True, False] ++ undefined)
[All {getAll = False},All {getAll = False},All {getAll = False}]
So far so good, but can we generalise g to return a monadic value a -> b -> m c? The following does not work, complaining that b is not in scope:
import Data.Traversable (mapAccumM) repminM :: (Traversable t, Monoid b, Monad m) => (a -> b) -> (a -> b -> m c) -> t a -> m (t c) repminM f g as = do (b, cs) <- mapAccumM (\acc a -> (f a <> acc,) <$> g a b) mempty as pure cs
To solve the riddle, let's rewrite repmin via fix:
repmin :: (Traversable t, Monoid b) => (a -> b) -> (a -> b -> c) -> t a -> t c repmin f g as = snd $ fix $ \(b, cs) -> mapAccumR (\acc a -> (f a <> acc, g a b)) mempty as
Now we can replace fix with mfix to obtain the solution:
repminM :: (Traversable t, Monoid b, MonadFix m) => (a -> b) -> (a -> b -> m c) -> t a -> m (t c) repminM f g as = fmap snd $ mfix $ \(~(b, cs)) -> mapAccumM (\acc a -> (f a <> acc,) <$> g a b) mempty as
For example,
>>> import Data.Monoid (Sum(..)) >>> repminM Sum (\a b -> print a >> pure (a + getSum b)) [3, 5, 2] 3 5 2 [13,15,12]
Incredibly, GHC is capable to do this transformation automatically, when {-# LANGUAGE RecursiveDo #-} is enabled. Namely, the following implementation of repminM works (note mdo instead of do):
{-# LANGUAGE RecursiveDo #-}
repminM
:: (Traversable t, Monoid b, MonadFix m)
=> (a -> b) -> (a -> b -> m c) -> t a -> m (t c)
repminM f g as = mdo
(b, cs) <- mapAccumM (\acc a -> (f a <> acc,) <$> g a b) mempty as
pure cs
Further reading:
- GHC User’s Guide, The recursive do-notation.
- Haskell Wiki, MonadFix.
- Levent Erkök, Value recursion in monadic computations, Oregon Graduate Institute, 2002.
- Levent Erkök, John Launchbury, A recursive do for Haskell, Haskell '02, 29-37, 2002.
- Richard S. Bird, Using circular programs to eliminate multiple traversals of data, Acta Informatica 21, 239-250, 1984.
- Jasper Van der Jeugt, Lazy layout, 2023.
class Monad m => MonadFix (m :: Type -> Type) where Source
Monads having fixed points with a 'knot-tying' semantics. Instances of MonadFix should satisfy the following laws:
- Purity
mfix (return . h) = return (fix h)- Left shrinking (or Tightening)
mfix (\x -> a >>= \y -> f x y) = a >>= \y -> mfix (\x -> f x y)- Sliding
-
mfix (liftM h . f) = liftM h (mfix (f . h)), for stricth. - Nesting
mfix (\x -> mfix (\y -> f x y)) = mfix (\x -> f x x)
This class is used in the translation of the recursive do notation supported by GHC and Hugs.
Methods
mfix :: (a -> m a) -> m a Source
The fixed point of a monadic computation. mfix f executes the action f only once, with the eventual output fed back as the input. Hence f should not be strict, for then mfix f would diverge.
Instances
fix f is the least fixed point of the function f, i.e. the least defined x such that f x = x.
When f is strict, this means that because, by the definition of strictness, f ⊥ = ⊥ and such the least defined fixed point of any strict function is ⊥.
Examples
We can write the factorial function using direct recursion as
>>> let fac n = if n <= 1 then 1 else n * fac (n-1) in fac 5 120
This uses the fact that Haskell’s let introduces recursive bindings. We can rewrite this definition using fix,
Instead of making a recursive call, we introduce a dummy parameter rec; when used within fix, this parameter then refers to fix’s argument, hence the recursion is reintroduced.
>>> fix (\rec n -> if n <= 1 then 1 else n * rec (n-1)) 5 120
Using fix, we can implement versions of repeat as fix . (:) and cycle as fix . (++)
>>> take 10 $ fix (0:) [0,0,0,0,0,0,0,0,0,0]
>>> map (fix (\rec n -> if n < 2 then n else rec (n - 1) + rec (n - 2))) [1..10] [1,1,2,3,5,8,13,21,34,55]
Implementation Details
© The University of Glasgow and others
Licensed under a BSD-style license (see top of the page).
https://downloads.haskell.org/~ghc/9.14.1/docs/libraries/base-4.22.0.0-66f8/Control-Monad-Fix.html